Question
Find the square of $x+ 3y$
✓
Answer
$(x + 3y)^2$
$ = (x)^2 + (3y)^2+ 2\times x \times 3y$
$= x^2 + 9y^2+ 6xy$
$ = (x)^2 + (3y)^2+ 2\times x \times 3y$
$= x^2 + 9y^2+ 6xy$
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