Gujarat BoardEnglish MediumSTD 8MATHSSquares and Square Roots2 Marks
Question
Find the square root of: $38\frac{11}{25}$
✓
Answer
We know, $\sqrt{38\frac{11}{25}}=\sqrt{\frac{961}{25}}=\frac{\sqrt{961}}{\sqrt{25}}$ Now, let us compute the square roots of the numerator and the denominator separately. $\sqrt{961}=31$ $\sqrt{25}=5$ $\therefore\sqrt{38\frac{11}{25}}=\frac{31}{5}$
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