Question
Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication,
$96$
$96$
✓
Answer
$(96)^2$
Here $a=9, b=6$
$(96)^2=96 \times 96=9216$
$\therefore(96)^2=9216$
Here $a=9, b=6$
| $\text{a}^2$ | $\text{2ab}$ | $\text{b}^2$ |
| $\ \ \ \ \ (9)^2\\ \ =81\\+\ \ {11}$ | $2\times9\times6\\=108\\ \ +3$ | $\ \ \ (6)^2\\=36$ |
| $92$ | $111$ |
$\therefore(96)^2=9216$
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