Question
Find the standard form of
$\frac{-18}{45}$
$\frac{-18}{45}$
✓
Answer
We have, $\frac{-18}{45}$
$
\because 18=2 \times 3 \times 3 \text { and } 45=3 \times 3 \times 5
$
$\therefore$ HCF of 18 and $45=3 \times 3=9$
On dividing numerator and denominator by their HCF, we get
$\frac{-18}{45}=\frac{-18÷9}{45÷9}=\frac{-2}{5}$
Hence, the standard form of $\frac{-18}{45}$ is $\frac{-2}{5}$.
$
\because 18=2 \times 3 \times 3 \text { and } 45=3 \times 3 \times 5
$
$\therefore$ HCF of 18 and $45=3 \times 3=9$
On dividing numerator and denominator by their HCF, we get
$\frac{-18}{45}=\frac{-18÷9}{45÷9}=\frac{-2}{5}$
Hence, the standard form of $\frac{-18}{45}$ is $\frac{-2}{5}$.
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