Question
Find the sum $2\frac{4}{5}+1\frac{3}{10}+3\frac{1}{15}$.
✓
Answer
We have, $2\frac{4}{5}+1\frac{3}{10}+3\frac{1}{15}$
$=\frac{14}{5}+\frac{13}{10}+\frac{46}{15}$
$\begin{array}{c|c}5&5,10,15\\\hline2&1,2,3\ \ \ \\\hline3&1,1,3\ \ \ \\\hline&1,1,1\ \ \ \end{array}$
$L.C.M$. of $5, 10$ and $15 = (5 × 2 × 3) = 30$
$(30\div5=6,6\times14=84)$
$(30\div10=3,3\times13=39)$ and $(30\div15=2,2\times46=92)$
$=\frac{84+39+92}{30}$
$=\frac{215}{30}$
$=\frac{43}{6}$
$=7\frac{1}{6}$
$=\frac{14}{5}+\frac{13}{10}+\frac{46}{15}$
$\begin{array}{c|c}5&5,10,15\\\hline2&1,2,3\ \ \ \\\hline3&1,1,3\ \ \ \\\hline&1,1,1\ \ \ \end{array}$
$L.C.M$. of $5, 10$ and $15 = (5 × 2 × 3) = 30$
$(30\div5=6,6\times14=84)$
$(30\div10=3,3\times13=39)$ and $(30\div15=2,2\times46=92)$
$=\frac{84+39+92}{30}$
$=\frac{215}{30}$
$=\frac{43}{6}$
$=7\frac{1}{6}$
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