Question
Find the sum: $\frac{2}{9}+\frac{5}{6}$
✓
Answer
$L.C.M.$ of $9$ and $6 = (2 × 3 × 3) = 18$
$\begin{array}{c|c}3&9,6\\\hline3&3,2\\\hline2&1,2\\\hline&1,1\end{array}$
Now, we know: $\frac{2}{9}=\frac{2\times2}{9\times2}=\frac{4}{18}$
$\frac{5}{6}=\frac{5\times3}{6\times3}=\frac{15}{18}$
Therefore, $\frac{2}{9}+\frac{5}{6}$ $=\frac{4}{18}+\frac{15}{18}$ $=\frac{(4+15)}{18}$ $=\frac{19}{18}$ $=1\frac{1}{18}$
$\begin{array}{c|c}3&9,6\\\hline3&3,2\\\hline2&1,2\\\hline&1,1\end{array}$
Now, we know: $\frac{2}{9}=\frac{2\times2}{9\times2}=\frac{4}{18}$
$\frac{5}{6}=\frac{5\times3}{6\times3}=\frac{15}{18}$
Therefore, $\frac{2}{9}+\frac{5}{6}$ $=\frac{4}{18}+\frac{15}{18}$ $=\frac{(4+15)}{18}$ $=\frac{19}{18}$ $=1\frac{1}{18}$
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