Question
Find the sum of: $\frac{7}{3}$ and $\frac{-4}{3}$
✓
Answer
Given, $\frac{7}{3}$ and $\frac{-4}{3}$
Sum, $=\frac{7}{3}+\Big(-\frac{4}{3}\Big )$$ [\therefore LCM$ of $3$ and $3 = 3]$
$=\frac{7}{3}-\frac{4}{3}$ $=\frac{7-4}{3}=\frac{3}{3}$ $=1$
Hence, the sum of $\frac{7}{3}$ and $\frac{-4}{3}$ is $1.$
Sum, $=\frac{7}{3}+\Big(-\frac{4}{3}\Big )$$ [\therefore LCM$ of $3$ and $3 = 3]$
$=\frac{7}{3}-\frac{4}{3}$ $=\frac{7-4}{3}=\frac{3}{3}$ $=1$
Hence, the sum of $\frac{7}{3}$ and $\frac{-4}{3}$ is $1.$
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