MCQ
Find the sum of series 62 + 72 +…………………..+ 152.
- A55
- B1185
- C1240
- D1385
Solution:
62 + 72 +………………..….. + 152
= (12 + 22 + 32 + …….. +152) – (12 + 22 + 32 + 42 + 52)
$=\frac{15\times16\times31}{6}-\frac{5\times6\times11}{6}$
$=1240-55=1185.$
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If $\sin\theta+\cos\theta=1,$ then the value of $\sin2\theta$ is equal to:
The value of $\cos^248^\circ-\sin^212^\circ$ is:
$\frac{\sqrt{5}+1}{8}$
$\frac{\sqrt{5}-1}{8}$
$\frac{\sqrt{5}+1}{5}$
$\frac{\sqrt{5}+1}{2\sqrt{2}}$
[Hint: Use $\cos^2\text{A}-\sin^2\text{B}=\cos(\text{A + B})\cos(\text{A}-\text{B})$]