Question
Find the surface area of a cuboid whose:
Length $=6 dm$, breadth $=8 dm$, height $=10 dm$.

Answer

Length of cuboid ( l $)=6 dm$
Breadth (b) $=8 dm$
Height (h) $=10 dm$
$\therefore \text { Surface area }=2(l \times b+b \times h+h \times l)$
$=2(6 \times 8+8 \times 10+10 \times 6) dm^2$
$=2(48+80+60) dm^2=2 \times 188=376 dm^2$

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