Question
Find the value and express as a rational number in standard form: $\frac{-40}{99}\div(-20)$

Answer

$\frac{-40}{99}\div(-20)=\frac{-40}{99}\times\frac{1}{-20}$ $=\frac{-2\times1}{99\times(-1)}=\frac{-2}{99}=\frac{2}{99}$

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