MCQ
Find the value of $a, \,b,\, c,$ and $d$ from the equation: $\left[\begin{array}{cc}a-b & 2 a+c \\ 2 a-b & 3 c+d\end{array}\right]=\left[\begin{array}{cc}-1 & 5 \\ 0 & 13\end{array}\right]$
  • A
    $a=0$,  $b=2 $,   $c=3$,   $d=4 $
  • $a=1$,  $b=2 $,   $c=3$,   $d=4 $
  • C
    $a=1$,  $b=2 $,   $c=3$,   $d=0 $
  • D
    $a=1$,  $b=3 $,   $c=3$,   $d=4 $

Answer

Correct option: B.
$a=1$,  $b=2 $,   $c=3$,   $d=4 $
b
$\left[\begin{array}{cc}a-b & 2 a+c \\ 2 a-b & 3 c+d\end{array}\right]=\left[\begin{array}{cc}-1 & 5 \\ 0 & 13\end{array}\right]$

As the two matrices are equal, their corresponding elements are also equal. Comparing the corresponding elements, we get:

$a-b=-1$            ........... $(1)$

$2 a-b=0$             ........... $(2)$

$2 a+c=5$             ........... $(3)$

$3 c+d=13$             ........... $(4)$

From $( 2 )$, we have :

$b=2 a$

Then, from $( 1 )$, we have :

$a-2a=-1$

$\Rightarrow$   $a=1$

$\Rightarrow$   $b=2$

Now, from $(3),$ we have :

$2 \times 1+c=5$

$\Rightarrow $  $c=3$

From $(4)$ we have :

$ 3 \times 3+d=13 $

$ \Rightarrow   $   $9+d=13 \Rightarrow d=4$

$\therefore $  $a=1$,  $b=2 $,   $c=3$,  and  $d=4 $

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