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Current Electricity — Physics STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 SciencePhysicsCurrent Electricity2 Marks
Question
Find the value of X in the given figure.
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Answer

From the principle of meterbridge
$\frac{X}{45}=\frac{11}{10045}$
$\Rightarrow \quad \frac{X}{45}=\frac{11}{55}$
$\Rightarrow \quad X =\frac{45 \times 11}{55}=9 \Omega$ Ans.

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