MCQ
Find the values of $a, b, c$ and $d$ respectively if $\left[\begin{array}{cc}2 a+b & a-2 b \\ 5 c-d & 4 c+3 d\end{array}\right]=\left[\begin{array}{cc}4 & -3 \\ 11 & 24\end{array}\right]$.
  • A
    $1,3,9,8$
  • 1, 2, 3, 4
  • C
    $1,4,8,10$
  • D
    $1,5,6,7$

Answer

Correct option: B.
1, 2, 3, 4
(b) : Since, $\left[\begin{array}{cc}2 a+b & a-2 b \\ 5 c-d & 4 c+3 d\end{array}\right]=\left[\begin{array}{cc}4 & -3 \\ 11 & 24\end{array}\right]$
$\therefore \quad 2 a+b=4 \ldots$..(i), $a-2 b=-3 \ldots$..ii), $5 c-d=11 \ldots$ (iii) and $4 c+3 d=24 \ldots$ (iv)
On solving (i) and (ii), we get $a=1, b=2$
On solving (iii) and (iv), we get $c=3, d=4$

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