Question
Find the volume, lateral surface area and the total surface area of a cube whose edges measures: $8\ dm, 5\ cm.$
✓
Answer
Edge of cube $(a) = 8\ dm\ 5\ cm = 85\ cm$.
$a.$ Volume $=a^3=(85)^3 \mathrm{~\ cm}^3$
$=85 \times 85 \times 85=614125 \mathrm{~\ cm}^3$
$b.$ Lateral surface area $=4 \mathrm{a}^2$
$=4 \times(85)^2 \mathrm{~\ cm}^2$
$=4 \times 85 \times 85=28900 \mathrm{~\ cm}^2$
$c.$ Total surface area $=6 \mathrm{a}^2=6(85)^2 \mathrm{~\ cm}^2$
$=6 \times 85 \times 85=43350 \mathrm{~\ cm}^2$
$a.$ Volume $=a^3=(85)^3 \mathrm{~\ cm}^3$
$=85 \times 85 \times 85=614125 \mathrm{~\ cm}^3$
$b.$ Lateral surface area $=4 \mathrm{a}^2$
$=4 \times(85)^2 \mathrm{~\ cm}^2$
$=4 \times 85 \times 85=28900 \mathrm{~\ cm}^2$
$c.$ Total surface area $=6 \mathrm{a}^2=6(85)^2 \mathrm{~\ cm}^2$
$=6 \times 85 \times 85=43350 \mathrm{~\ cm}^2$
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