Question
Find the volume of a cube whose diagonals is $\sqrt{48} \ cm$.
✓
Answer
Given that:
Diagonal of a cube $=\sqrt{48} \ cm$
i.e, $\sqrt{3} \times 1=\sqrt{48} \ldots[\because$ Diagonal of cube $=\sqrt{3} \times 1]$
$ I=\frac{\sqrt{48}}{\sqrt{3}}$
$I=\sqrt{\frac{48}{3}}$
$=\sqrt{16}$
$=4 \ cm$
$\therefore$ Side $( l )=4 \ cm$
Now,
Volume of cube
$=1^3$
$=|\times| \times \mid$
$=4 \times 4 \times 4$
$=16 \times 4$
$=64 \ cm ^3$
$\therefore$ Volume of Cube $=64 \ cm ^3$.
Diagonal of a cube $=\sqrt{48} \ cm$
i.e, $\sqrt{3} \times 1=\sqrt{48} \ldots[\because$ Diagonal of cube $=\sqrt{3} \times 1]$
$ I=\frac{\sqrt{48}}{\sqrt{3}}$
$I=\sqrt{\frac{48}{3}}$
$=\sqrt{16}$
$=4 \ cm$
$\therefore$ Side $( l )=4 \ cm$
Now,
Volume of cube
$=1^3$
$=|\times| \times \mid$
$=4 \times 4 \times 4$
$=16 \times 4$
$=64 \ cm ^3$
$\therefore$ Volume of Cube $=64 \ cm ^3$.
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