Question
Find the zero of the polynomial:
$\text{p}(\text{x})=\text{ax},\ \text{a}\neq0$
$\text{p}(\text{x})=\text{ax},\ \text{a}\neq0$
✓
Answer
$\text{p}(\text{x})=0$
$\Rightarrow\text{ax}+\text{b}=0$
$\Rightarrow\text{x}=-\frac{\text{b}}{\text{a}}$
Hence, $-\frac{\text{b}}{\text{a}}$ is the zero of the polynomial p(x).
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Write the axis on the given point lies.
(0, -1)
Write the remainder when the polynomial $f(x)=x^3+x^2-3 x+2$ is divided by $x+1$.
→The following figure lie on the same base and between the same parallels. In such a case, write the common base and the two parallels.
Find: 321/5
Identify constant, linear, quadratic, cubic and quadrtic polynomials from the following:
1 + x + x2
1 + x + x2
Factorise:
x3 + 27
x3 + 27
Expand using appropriate identity: (-2x + 5y - 3z)2
Simplify:
$3^\frac{1}{4}\times5^\frac{1}{4}$
→$3^\frac{1}{4}\times5^\frac{1}{4}$
Find two solutions for equation: 2x + 5y = 0
Factorise:
8a3 + 27b3 + 36a2b + 54ab2
8a3 + 27b3 + 36a2b + 54ab2