Question
Find three different irrational numbers between the rational numbers $\frac {5} {9} $ and $\frac {9} {11} $.
✓
Answer
Thus, $\frac {5} {7}$ = 0.714285 ... = $0 . \overline{714285}$
Thus, $\frac {9} {11} $ = 0.8181 ... = $0 . \overline{81}$
Three different irrational numbers between the rational $\frac {5} {9} $ and $\frac {9} {11} $ can be taken as
0.75 075007500075000075 ...
0.7670767000767 ...,
0.808008000800008 ...
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If $1176=2^\text{a}\times3^\text{b}\times7^\text{c},$ find a, b and c.
→Express the following equation in the form ax + by + c = 0 and indicate the values of a, b, c in case.
3y - 2x = 6
3y - 2x = 6
Find the following products: $(4x - 5y)(16x^2 + 20xy + 25y^2)$
→Verify that: $2$ and $-3$ are the zeros of the polynomial $q(x) = x^2 + x - 6.$
→Factorize the following expressions: $x^3 - 8y^3 + 27z^3 + 18xyz$
→Find the total surface area of a hemisphere and a solid hemisphere each of radius 10cm $(\pi=3.14)$
→Factorise:$2x^2 + 3x - 90$
→Find the value of $q(y) = 3y^3 - 4y + \sqrt{11}$ at $y = 2.$
→The marks obtained by 90 students of a school in mathematics out of 100 are given as under:
From these students, a student is chosen at random.
What is the probability that the chosen student:
|
Marks
|
0 - 20
|
20 - 30
|
30 - 40
|
40 - 50
|
50 - 60
|
60 - 70
|
70 and above
|
|
Number of students
|
7
|
8
|
12
|
25
|
19
|
10
|
9
|
What is the probability that the chosen student:
- Gets 20% or less marks?
- Gets 60% or more marks?
The average height of 30 boys was calculated to be 150cm. It was detected later that one value of 165cm was wrongly copied as 135cm for the computation of the mean. Find the correct mean.