Question
Find two consecutive natural numbers whose product is $20.$

Answer

Let the two consecutive natural numbers be $ 'x'$ and $'x + 1'$
Given that product of the natural numbers is $20$
$ \text { Hence, } x(x+1)=20$
$\Rightarrow x^2+x=20$
$\Rightarrow x^2+x-20=0$
$\Rightarrow x^2+5 x-4 x-20=0$
$\Rightarrow x(x+5)-4(x+5)=0$
$\Rightarrow x=-5 \text { or } x=4$
Considering positive value of x as $\text{x}\in\text{N}$
For $r = 4, x + 1 = 4 + 1 = 5$
The two consecutive natural numbers are $4$ as $5$

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