MCQ
Fluorine is a better oxidising agent than $B{r_2}$. It is due to
- ASmall size of fluorine
- BMore electron repulsion in fluorine
- CMore electronegativity of fluorine
- ✓Non-metallic nature of fluorine
✓
Answer
Correct option: D.
Non-metallic nature of fluorine
d
$F$ is more electronegative than $Br$. Therefore it can easily accept $e ^{-}$ and oxidise others.
$F$ is more electronegative than $Br$. Therefore it can easily accept $e ^{-}$ and oxidise others.
Therefore $F _2$ is better oxidising agent than $Br _2$
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