MCQ
Fluorine is a stronger oxidising agent than chlorine in aqueous solution. This is attributed to many factors except
- AHeat of dissociation
- ✓Electron affinity
- CHeat of hydration
- DIonisation potential
✓
Answer
Correct option: B.
Electron affinity
b
It’s Obvious.
It’s Obvious.
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$\begin{matrix}
O\,\,\, \\
||\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}- \\
\end{matrix}\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}-C-C{{H}_{3}}\xrightarrow[\Delta ]{{{(N{{H}_{4}})}_{2}}C{{O}_{3}}}\xrightarrow[\Delta ]{CC{{l}_{3}}C{{O}_{2}}Na}\underset{(major)}{\mathop{(B)}}\, \\
\end{matrix}$
→O\,\,\, \\
||\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}- \\
\end{matrix}\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}-C-C{{H}_{3}}\xrightarrow[\Delta ]{{{(N{{H}_{4}})}_{2}}C{{O}_{3}}}\xrightarrow[\Delta ]{CC{{l}_{3}}C{{O}_{2}}Na}\underset{(major)}{\mathop{(B)}}\, \\
\end{matrix}$
Product $(B)$ of above reaction is
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