MCQ
Fluorine with dilute $NaOH$ gives
- ✓$O{F_2}$
- B${O_3}$
- C${O_2}$
- D$HF$ and ${O_2}$
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| Item $I$ | Item $II$ |
| $A$ Allosteric effect | $P$ Molecule binding to the active site of enzyme |
| $B$ Competitive inhibitor | $Q$ Molecule crucial for communication in the body |
| $C$ Receptor | $R$ Molecule binding to a site other than the active site of enzyme |
| $D$ Poison | $S$ Molecule binding to the enzyme covalently |
The product $B$ is
${C_6}{H_5}C{H_2}CH(OH)CH{(C{H_3})_2}\xrightarrow{{conc.\,{H_2}S{O_4}}}\,?$
