For a binomial variate X, if n=3 and P(X=1)=8 P(X = 3), then p = - Vidyadip

Question

For a binomial variate X, if $\text{n}=3$ and $\text{P(X}=1)=8\text{ P(X = 3}),$ then p =

✓

Answer

Get the step-by-step solution for this question inside the Vidyadip app.

Get the answer in the app

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Probability→Probability — all question types→MATHS STD 12 Science question papers→Rajasthan Board STD 12 Science question papers→Rajasthan Board question paper generator→

Similar questions

The value of $ \left( {{{\tan }^{ - 1}}\pi + {{\tan }^{ - 1}}\left( {\frac{1}{\pi }} \right)} \right) + {\tan ^{ - 1}}\sqrt 3 - {\sec ^{ - 1}}( - 2)$ is equal to

$ \frac{{ - \pi }}{3}$
$ \frac{{ \pi }}{6}$
$ \frac{{ 2 \pi }}{3}$
$ \pi$

The value of the determinant $\left|\begin{array}{ccc}2 & 7 & 1 \\ 1 & 1 & 1 \\ 10 & 8 & 1\end{array}\right|$ is

$\int\limits^\text{e}_1\log\text{x}\text{ dx}=$

1
e - 1
e + 1
0

Choose the correct answer from the given four options. On using elementary row operation $R_1 \rightarrow R_1 – 3R_2$ in the following matrix equation $\begin{bmatrix}4&2\\3&3\end{bmatrix}=\begin{bmatrix}1&2\\0&3\end{bmatrix}\begin{bmatrix}2&0\\1&1\end{bmatrix},$ we have:

If $\tan^{-1}(\text{x}-1)+\tan^{-1}\text{x}+\tan^{-1}(\text{x}+1)=\tan^{-1}3\text{x},$ then the values of x are:

$\pm\frac{1}{2}$
$0,\frac{1}{2}$
$0,-\frac{1}{2}$
$0,\pm\frac{1}{2}$

Choose the correct answer from the given four options.The general solution of the differential equation $(\text{e}^{\text{x}}+1)\text{ydy}=(\text{y}+1)\text{e}^{\text{x}}$ is:

$(\text{y}+1)=\text{k}(\text{e}^{\text{x}}+1)$
$\text{y}+1=\text{e}^{\text{x}}+1+\text{k}$
$\text{y}=\log\left\{\text{k}(\text{y}+1)(\text{e}^{\text{x}}+1)\right\}$
$\text{y}=\log\left\{\frac{\text{e}^{\text{x}}+1}{\text{y}+1}\right\}+\text{k}$

The solution set of the inequation 3x + 2y > 3 is:

$\int\frac{2}{(\text{e}^{\text{x}}+\text{e}^{-\text{x}})^2}\text{ dx}=$

$\frac{-\text{e}^{-\text{x}}}{\text{e}^{\text{x}}+\text{e}^{-\text{x}}}+\text{C}$
$-\frac{1}{\text{e}^{\text{x}}+\text{e}^{-\text{x}}}+\text{C}$
$\frac{-1}{(\text{e}^{\text{x}}+1)^2}+\text{C}$
$\frac{1}{\text{e}^{\text{x}}-\text{e}^{-\text{x}}}+\text{C}$

The maximum value of Z = 4x + 3y subjected to the constraints $2\text{x}+3\text{y}\leq18,$ $\text{x}+\text{y}\geq10;\text{x},\text{y}\geq0$ is:

36
40
20
None of these

The straigth line $\frac{\text{x}-3}{3}=\frac{\text{y}-2}{1}=\frac{\text{z}-1}{0}$ is:

parallel to x-axis
parallel to y-axis
parallel to z-axis
perpendicular to z-axis