MCQ
For a given triode $\mu=20$. The load resistance is $1.5$ times the anode resistance. The maximum gain will be
- A$16$
- ✓$12$
- C$10$
- DNone of the above
✓
Answer
Correct option: B.
$12$
$ \text { Voltage gain } A_v=\frac{\mu}{1+\frac{r_p}{R_L}}$
$ \because R_L=1.5 r_p \Rightarrow A_v=\frac{\mu}{1+\frac{r_p}{1.5 r_p}}=\frac{3}{5} \mu=\frac{3}{5} \times 20=12 .$
$ \because R_L=1.5 r_p \Rightarrow A_v=\frac{\mu}{1+\frac{r_p}{1.5 r_p}}=\frac{3}{5} \mu=\frac{3}{5} \times 20=12 .$
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