For a real function f(x)=6 x^3-5^x+15, find the value of f(0). - Vidyadip

Question

For a real function $f(x)=6 x^3-5^x+15$, find the value of $f(0)$.

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Answer

$f(x)=6 x^3-5^x+15$
$\therefore f(0)=6 \times 0-5^0+15=0-1+15=14$
$\therefore f(0)=14$

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