For a system in equilibrium, =0 under conditions of constant: - Vidyadip

MCQ

For a system in equilibrium, $\triangle\text{G}=0$ under conditions of constant:

A
Temperature and pressure.
B
Temperature and volume.
C
Energy and volume.
D
Pressure and volume.

✓

Answer

Temperature and pressure.

Explanation:

When a system is at equilibrium under constant temperature and pressure, its free energy change is zero $(\triangle\text{G}=0)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Equilibrium→Equilibrium — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

Which molecule has zero dipole moment

Which of the following conditions will always lead to a non-spontaneous change

Which of the following sets represent the normal physical states of the elements concerned at $25\,^oC$ and one bar pressure, with $\Delta H^o(formation)\, = 0$

Which of the following odd $e^-$ species is planar ?

The oxidation states of the most electronegative element in the products of the reaction of $Ba{O_2}$ with dilute ${H_2}S{O_4}$ are

The ions $O^{2-}, F^-, Na^+, Mg^{2+}$ and $Al^{3+}$ are isoelectronic. Their ionic radii show

Elements upto atomic number $103$ have been synthesized and studied. If a newly discovered element is found to have an atomic number $106,$ its electronic configuration will be

Amongst $BeF _{2}, BF _{3}, H _{2} O , NH _{3}, CCl _{4}$ and $HCl$, the number of molecules with non-zero net dipole moment is ...... .

Give the functional group of the following.-OH

$K_{sp}$ for $BaSO_4$ at $25\,^oC$ is $1.1 \times 10^{-10}$ . To make the new solubility equal to $1.1 \times 10^{-8}$ , it is necessary to use the solution of $Na_2SO_4$ of the following concentration .......$M$