MCQ
For a transistor, in a common emitter arrangement, the alternating current gain $b$ is given by
  • $\beta=\left(\frac{\Delta I }{\Delta I _{ B }}\right)_{ vc }$
  • B
     $\beta=$ $\left(\frac{\Delta I _{ E }}{\Delta I _{ C }}\right)_{ v c }$
  • C
     $\beta=\left(\frac{\Delta I _{ c }}{\Delta I _{ E }}\right)_{ v c }$
  • D
     $\beta=\left(\frac{\Delta II _{ E }}{\Delta IC _{ C }}\right)_{ v c }$

Answer

Correct option: A.
$\beta=\left(\frac{\Delta I }{\Delta I _{ B }}\right)_{ vc }$
$\beta=\left(\frac{\Delta I _{ C }}{\Delta I _{ B }}\right)_{ vc }$

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