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Electronics — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsElectronics1 Mark
MCQ
For a transistor, in a common emitter arrangement, the alternating current gain $\beta$ is given by
  • ✓
    $\beta=\left(\frac{\Delta I_C}{\Delta I_B}\right)_{V_C}$
  • B
    $\beta=\left(\frac{\Delta I_B}{\Delta I_C}\right)_{V_C}$
  • C
    $\beta=\left(\frac{\Delta I_C}{\Delta I_E}\right)_{V_C}$
  • D
    $\beta=\left(\frac{\Delta I_E}{\Delta I_C}\right)_{V_C}$
✓

Answer

Correct option: A.
$\beta=\left(\frac{\Delta I_C}{\Delta I_B}\right)_{V_C}$

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