For a transistor the parameter =99. The value of the parameter is - Vidyadip

MCQ

For a transistor the parameter $\beta=99$. The value of the parameter $\alpha$ is

A
$0.9$
✓
$0.99$
C
$1$
D
$9$

✓

Answer

Correct option: B.

$0.99$

$\alpha=\frac{\beta}{1+\beta}=\frac{99}{1+99}=0.99$.

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