MCQ
For $AB$ bond if percent ionic character is plotted against electronegativity difference $(X_A -X_B),$ the shape of the curve would look like The correct curve is
- A$(A)$
- B$(B)$
- ✓$(C)$
- D$(D)$
$\Delta E . N .=1.7 \Rightarrow 50\,\%$ ionic and $50 \,\%$ covalent
$\Delta E . N .\,>\,1.7 \Rightarrow$ more than $50\, \%$ ionic and less than $50 \,\%$ covalent
$\Delta E . N .\,<\,1.7 \Rightarrow$ less than $50\, \%$ ionic and more than $50\, \%$ covalent
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| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{Bi}^{3+} \longrightarrow(\mathrm{BiO})^{+}$ | $(P)$ Heat |
| $(B)$ $\left[\mathrm{AlO}_2\right]^{-} \longrightarrow \mathrm{Al}(\mathrm{OH})_3$ | $(Q)$ Hydrolysis |
| $(C)$ $\mathrm{SiO}_4^{4-} \longrightarrow \mathrm{Si}_2 \mathrm{O}_7^{6-}$ | $(R)$ Acidification |
| $(D)$ $\left(\mathrm{B}_4 \mathrm{O}_7^{2-}\right) \longrightarrow\left[\mathrm{B}(\mathrm{OH})_3\right]$ | $(S)$ Dilution by water |
$CH_3-CH = CH -CH_2 -CH_2 -CH(CH_3)_2$
$(A)$ $(B)\,\,\,(C)$ $(D)$ $(E)\,\,\,(F)$
arrange them in decreasing order of reactivity towards free radical substitution