MCQ
For any two sets A and B, $\text{A}\cap\text{(A}\cup\text{B)}=$
- AA
- BB
- C$\phi$
- DNone of these
Solution:
$\text{A}\cap\text{(A}\cup\text{B)}=\text{(A}\cap\text{A)}\cup\text{(A}\cap\text{B)}=\text{A}\cup\text{(A}\cap\text{B)}=\\\text{AA}\cap\text{(A}\cup\text{B)}=\text{(A}\cap\text{A)}\cup\text{(A}\cap\text{B)}=\text{A}\cup\text{(A}\cap\text{B)}=\text{A.}$
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$\text{A}:\cos\text{a}+\cos\text{b}+\cos\text{g}=0$
$\text{B}:\sin\text{a}+\sin\text{b}+\sin\text{g}=0$
If
$\cos(\beta-\text{y})+\cos(\text{y}-\alpha)+\cos(\alpha-\beta)=\frac{-3}{2}$ then: