MCQ
For function $f(x)={\left( {1 + \frac{1}{x}} \right)^x}$  Which one of the following limits tends to unity'
  • A
    $\mathop {Lim}\limits_{x \to \infty } \,\,{\rm{f}}(x)$
  • $\mathop {Lim}\limits_{x \to {0^ + }} \,\,{\rm{f}}(x)$
  • C
    $\mathop {Lim}\limits_{x \to  - {1^ - }} \,\,{\rm{f}}(x)$
  • D
    $\mathop {Lim}\limits_{x \to  - \infty } \,\,{\rm{f}}(x)$

Answer

Correct option: B.
$\mathop {Lim}\limits_{x \to {0^ + }} \,\,{\rm{f}}(x)$
b

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Find the value of $x, \,y$ and $z$ from the following equation : $\left[\begin{array}{ll}4 & 3 \\ x & 5\end{array}\right]=\left[\begin{array}{ll}y & z \\ 1 & 5\end{array}\right]$
Area bounded between the parabola y2 = 4ax and its latus rectum is:
  1. $\frac{1}{3}\text{a }\text{sq}.\text{units}$
  2. $\frac{1}{3}\text{a}^2\text{ sq}.\text{units}$
  3. $\frac{8}{3}\text{a}\text{ sq}.\text{units}$
  4. $\frac{8}{3}\text{a}^2\text{ sq}.\text{units}$
Let $A(3, 0, -1), B(2, 10, 6)$ and $C(1, 2, 1)$ be the vertices of a triangle and $M$ be the midpoint of $AC$. If $G$ divides $BM$ in the ratio, $2 : 1$, then $\cos \,\left( {\angle GOA} \right)$ ($O$ being he origin) is equal to
If a curve passes throught origin, such that length of subnormal is equal to one more than square of ordinate, then
Let $y=\{x\}^{[x]}$  where $\{x\}$ denotes the fractional part of $x$ $ \&$ $ [x] $ denotes greatest integer $ \le x,$  then $\int\limits_0^3 {\,y\,dx} $=
Let $A$ be $2$$ \times $$2$ matrix

Statement $-1 :$  $adj\left( {adj\;A} \right) = A$

Statement $-2 :$ $\left| {adj\;A} \right| = \left| A \right|$

If $f\left( x \right) = \left| \begin{array}{*{20}{c}}
{\cos x}&x&1\\
{2\sin x}&{{x^2}}&{2x}\\
{\tan x}&x&1
\end{array}\right|$ , then $\mathop {\lim }\limits_{x \to 0} \frac{{f'\left( x \right)}}{x}$
The straight line $\frac{\text{x}-3}{3}=\frac{\text{y}-2}{1}=\frac{\text{z}-1}{0}$ is:
  1. Parallel to x-axis
  2. Parallel to y-axis
  3. Parallel to z-axis
  4. Perpendicular to z-axis
The general solution of ${x^2}\frac{{dy}}{{dx}} = 2$ is
If $c = \frac {1}{2}$ and $f(x) = 2x -x^2$ , then interval of $x$ in which $LMVT$, is applicable, is