MCQ
For ${H_3}P{O_3}$ and ${H_3}P{O_4}$ the correct choice is
- ✓${H_3}P{O_3}$ is dibasic and reducing
- B${H_3}P{O_3}$ is dibasic and non-reducing
- C${H_3}P{O_4}$ is tribasic and reducing
- D${H_3}P{O_3}$ is tribasic and non-reducing
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$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_2} = CH - C{H_2} - C - H}
\end{array} \to C{H_3} - C{H_2} - C{H_2} - C{H_2}OH$

$2H^+ + 2e^- + \frac{1}{2}O_2\longrightarrow H_2O_{(l)} ; $
$E^o = +1.23\, V$
$Fe^{2+} + 2e^- \longrightarrow Fe_{(s)} ;\ E^o = -0.44\,V$