MCQ
For the complexes showing the square pyramidal structure, the $d-$ orbital involved in the hybridisation is
- ✓$d_{x^2-y^2}$
- B$d_{z^2}$
- C$d_{xy}$
- D$d_{xz}$
When $d_{z^{2}}$ orbital is involved in the hybridization, the geometry is trigonal bipyramidal.
When $d_{x^{2}-y^{2}}$ orbital is involved in the hybridization, the geometry is square pyramidal.
Hence the correct option is A.
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| $List-I$ (Compound) | $List-II$ (Shape) |
| $(A)$ $BrF _{5}$ | $(I)$ bent |
| $(B)$ $\left[ CrF _{6}\right]^{3-}$ | $(II)$ square pyramidal |
| $(C)$ $O _{3}$ | $(III)$ trigonal bipyramidal |
| $(D)$ $PCl _{5}$ | $(IV)$ octahedral |
Choose the correct answer from the options given below.


$(I)$ $\phi -CH_3$
$(II)$ $\phi -CH_2-CH_3$
$(III)$ $\phi -CH(CH_3)_2$
$(IV)$ $\phi-C(CH_3)_3$
towards electrophilic substitution will be - [where $\phi =C_6H_5$]