
- ✓$9$
- B$5$
- C$0$
- D$14$

$\mathrm{i}_{5 \mathrm{k}}=\frac{120-50}{5 \mathrm{k}}=14\, \mathrm{mA}$
$\mathrm{i}_{2}=(14-5) \mathrm{mA}=9\, \mathrm{mA}$
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${ }_{92} \mathrm{X}^{236} \rightarrow{ }_{56} \mathrm{Y}^{141}+{ }_{36} \mathrm{Z}^{92}+3 \mathrm{R}$
The identity of emitted particles $(R)$ is :
Statement $I$ : A uniform wire of resistance $80\,\Omega$ is cut into four equal parts. These parts are now connected in parallel. The equivalent resistance of the combination will be $5\,\Omega$.
Statement $II :$ Two resistance $2\,R$ and $3\,R$ are connected in parallel in a electric circuit. The value of thermal energy developed in $3\,R$ and $2\,R$ will be in the ratio $3:2.$
In the light of the above statements, choose the most appropriate answer from the options given below