Question
For the equation given below, find the slope and the $y-i$ntercept$:4y + 9 = 0$
✓
Answer
Equation of any straight line in the form $y = mx + c,$
where slope$ = m($co$-$efficient of $x)$ and $y-$intercept $= c($constant term$)$
$4y + 9 = 0$
$4y = 0 · x - 9 y$
$=\frac{0}{4} x-\frac{9}{4}$
$y=0 \cdot x+$$\left(-\frac{9}{4}\right)$
Therefore,
slope $=$ co$-$efficient of $x = 0$
$y-$intercept $=$ constant term $= -\frac{9}{4}$
where slope$ = m($co$-$efficient of $x)$ and $y-$intercept $= c($constant term$)$
$4y + 9 = 0$
$4y = 0 · x - 9 y$
$=\frac{0}{4} x-\frac{9}{4}$
$y=0 \cdot x+$$\left(-\frac{9}{4}\right)$
Therefore,
slope $=$ co$-$efficient of $x = 0$
$y-$intercept $=$ constant term $= -\frac{9}{4}$
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