$SO_2Cl_2(g) \rightleftharpoons SO_2(g) + Cl_2(g)$ , what is the temperature at which $\frac{{{K_p}(atm)}}{{{K_c}(M)\,}} = \frac{1}{3}$ ? ......$K$
- A$0.027$
- B$0.36$
- C$36.54$
- ✓$4.06$
$SO_2Cl_2(g) \rightleftharpoons SO_2(g) + Cl_2(g)$ , what is the temperature at which $\frac{{{K_p}(atm)}}{{{K_c}(M)\,}} = \frac{1}{3}$ ? ......$K$
$\frac{\mathrm{K}_{\mathrm{p}}}{\mathrm{K}_{\mathrm{c}}}=(\mathrm{RT})^{\Delta \mathrm{n}}=0.0821 \times \mathrm{T}$
$\frac{1}{3}=0.0821 \times \mathrm{T}$
$\frac{1}{3 \times 0.0821}=\mathrm{T}$
$4.06\, \mathrm{K}=\mathrm{T}$
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$3 s^{2}$; $3 s^{2} 3 p^{1}$; $3 s ^{2} 3 p ^{3}$; $3 s^{2} 3 p^{4}$
The correct order of first ionization enthalpy for them is.
(Assume: Momentum is conserved when photon is absorbed. Use: Planck constant $=6.6 \times 10^{-34} J s$, Avogadro number $=6 \times 10^{23} mol ^{-1}$, Molar mass of $He =4 g mol ^{-1}$ )

$(a)$ $NCl_3$ is formed when $Cl_2$ is present in excess.
$(b)$ $N_2$ is formed when $Cl_2$ is present in excess.
$(c)$ $N_2$ is formed when $NH_3$ is present in excess.
$(d)$ $NCl_3$ is formed when $NH_3$ is present in excess.
Correct option are
