MCQ
For the function $f(x)\, = \frac{{{{\log }_e}(1 + x) - {{\log }_e}(1 - x)}}{x}$ to be continuous at $x = 0,$ the value of $f(0),$ should be
  • A
    $-1$
  • B
    $0$
  • C
    $-2$
  • $2$

Answer

Correct option: D.
$2$
d
(d) By $L-$ Hospital’s rule $\mathop {\lim }\limits_{x \to 0} f(x)$ is $2$. 

Therefore, for $f(x)$ to be continuous, the value of function should be $2$.

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