Question
For the G.P.
If $a=\frac{7}{243}, r=3$, find $t_6$
If $a=\frac{7}{243}, r=3$, find $t_6$
$\begin{aligned} t _{ n } & = ar ^{ n -1} \\ \therefore \quad t _6 & =\frac{7}{243} \times(3)^{6-1} \\ & =\frac{7}{243} \times 3^5 \\ & =7\end{aligned}$
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$\frac{6 !-4 !}{4 !}$
$\overline{\left(\frac{ z _1}{ z _2}\right)}=\frac{\overline{ z }_1}{\overline{ z }_2}$