Question
For the G.P.
If $r=-3$ and $t_6=1701$, find $a$.
If $r=-3$ and $t_6=1701$, find $a$.
$\begin{array}{ll} & t _{ n }=a r^{n-1} \\ \therefore & t _6=a(-3)^{6-1} \\ \therefore & 1701=a(-3)^5 \\ \therefore & a =\frac{1701}{-243} \\ \therefore & a =-7\end{array}$
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$f(x)=\log 10\left(x^2-5 x+6\right)$
if its current worth is Rs. 15 Lac. [Given: $(1.05)^5=1.28,(1.05)^6=1.34$ ]