MCQ
For the reaction ${H_2}O(s)$ $\rightleftharpoons$ ${H_2}O(l)$ at ${0\,^o}C$ and normal pressure
  • A
    $\Delta H > T\Delta S$
  • $\Delta H = T\Delta S$
  • C
    $\Delta H = \Delta G$
  • D
    $\Delta H < T\Delta S$

Answer

Correct option: B.
$\Delta H = T\Delta S$
(b)${H_2}{O_{(g)}}$ $ \rightleftharpoons $ ${H_2}{O_{(l)}}$
we know $\Delta G = \Delta H - T\Delta S$
at equilibrium $\Delta G = 0$
Therefore $\Delta H = T\Delta S$.

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