MCQ
For the reaction $PC{l_5}_{(g)}$ $\rightleftharpoons$ $PC{l_3}_{(g)} + C{l_2}_{(g)}$
- A${K_p} = {K_c}$
- B${K_p} = {K_c}{(RT)^{ - 1}}$
- ✓${K_p} = {K_c}(RT)$
- D${K_p} = {K_c}{(RT)^2}$
${K_p} = {K_c}(RT)$
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${K_p} = 8 \times {10^{ - 2}}$$C{O_{2(g)}} + {C_{(s)}} \to 2C{O_{(g)}}$ ; ${K_p} = 2$
$CaC{{O}_{3(s)}}\xrightarrow{\Delta }Ca{{O}_{(s)}}+C{{O}_{2}}\uparrow $; ${{K}_{p}}=8\times {{10}^{-2}}$
| Compound | Weight $\%$ of $P$ | Weight $\%$ of $Q$ |
| $1$ | $50$ | $50$ |
| $2$ | $44.4$ | $55.6$ |
| $3$ | $40$ | $60$ |
$(A)$ If empirical formula of compound $3$ is $P_3 Q_4$, then the empirical formula of compound $2$ is $P_3 Q_5$.
$(B)$ If empirical formula of compound $3$ is $P _3 Q _2$ and atomic weight of element $P$ is $20$ , then the atomic weight of $Q$ is $45$ .
$(C)$ If empirical formula of compound $2$ is $PQ$, then the empirical formula of the compound $1$ is $P _5 Q _4$.
$(D)$ If atomic weight of $P$ and $Q$ are $70$ and $35$ , respectively, then the empirical formula of compound $1$ is $P _2 Q$.