MCQ
For the reaction$,\text{C}_2\text{​H}_5\text{​OH}+\text{HX}\xrightarrow{\text{Zn}\text{X}_2}​​\text{C}_2\text{​H}_5\text{​X},$ the order of reactivity is:
  • A
    $\ce{HI > HCl > HBr}$
  • $\ce{HI > HBr > HCl}$
  • C
    $\ce{HCl> HBr > HI}$
  • D
    $\ce{HBr > HI > HCl}$

Answer

Correct option: B.
$\ce{HI > HBr > HCl}$
Because the reaction follows $S_{N_1}$ mechanism and hence the halide formed is stable when it is of a larger size and size increases down the group$. \ce{I > Br > Cl}.$

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