MCQ
For the system $A_{(g)} + 2B_{(g)}$ $\rightleftharpoons$ $C_{(g)}$, the equilibrium concentrations are $(A) 0.06$ mole/litre $(B) 0.12$ mole/litre $(C) 0.216$ mole/litre. The ${K_{eq}}$ for the reaction is
  • $250$
  • B
    $416$
  • C
    $4 \times {10^{ - 3}}$
  • D
    $125$

Answer

Correct option: A.
$250$
(a) For reaction $A + 2B$ $ \rightleftharpoons $ $ C$

$K = \frac{{[C]}}{{[A]\,\,{{[B]}^2}}} = \frac{{0.216}}{{0.06 \times 0.12 \times 0.12}} = 250$.

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