MCQ
For the transformation the reagent used is


- ✓$LiAlH_4$
- B$H_3PO_2$
- C$H_3O^+$
- D$H_2 / Pt$

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$X$ is

| Experiment | $\frac{[ X ]}{ mol \;L ^{-1}}$ | $\frac{[ Y ]}{ mol\; L ^{-1}}$ | $\frac{\text { Initial rate }}{ mol\; L ^{-1}\; min ^{-1}}$ |
| $I$ | $0.1$ | $0.1$ | $2 \times 10^{-3}$ |
| $II$ | $0.2$ | $0.2$ | $4 \times 10^{-3}$ |
| $III$ | $0.4$ | $0.4$ | $M \times 10^{-3}$ |
| $IV$ | $0.1$ | $0.2$ | $2 \times 10^{-3}$ |
Examine the data of table and calculate ratio of numerical value of $M$
$Ag\left( s \right)\left| {AgBr\left( s \right)\,\left| {B{r^ - }\left( {0.01\,M} \right)} \right|\,\left| {{I^ - }\left( {0.02\,M} \right)} \right|\,AgI\left( s \right)} \right|Ag\left( s \right)$
the correct information is
[Given : $K_{sp}\,\left( {AgBr} \right) = 4 \times {10^{ - 13}}$ ,
$K_{sp}\,\left( {AgI} \right)$ $ = 8 \times {10^{ - 17}},\frac{{2.303\,RT}}{F} = 0.06\,V,\,\log \,2 = 0.3]$