MCQ
For which of the following processes $\Delta\text{S}$ is negative?
  • A
    H2(g) → 2H(g)
  • B
    N2 (g, 1atm) → N2 (g, 5atm)
  • C
    2SO3(g) → 2SO2(g) + O2(g)
  • D
    C(diamond) → C(graphite)

Answer

  1. N2 (g, 1atm) → N2 (g, 5atm)

Explanation:

At higher pressure N2(g) will have less entropy, i.e. $\Delta\text{S}$ will be -ve because molecules will be less free to move at high pressure.

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