MCQ
Force constant of a spring $(K)$ is synonymous to
- ✓$\frac{YA}{L}$
- B$\frac{YL}{A}$
- C$\frac{AL}{Y}$
- D$ALY$
✓
Answer
Correct option: A.
$\frac{YA}{L}$
a
$\mathrm{Y}=\frac{\mathrm{FL}}{\mathrm{A} \Delta \mathrm{L}}$
$\mathrm{Y}=\frac{\mathrm{FL}}{\mathrm{A} \Delta \mathrm{L}}$
Or $\mathrm{F}=\left(\frac{\mathrm{YA}}{\mathrm{L}}\right) \Delta \mathrm{L}$
Comparing this with $\mathrm{F}=\mathrm{K} \Delta \mathrm{L}$
$\mathrm{K}=\frac{\mathrm{YA}}{\mathrm{L}}$
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