MCQ
Four boys and three girls stand in a queue for an interview, probability that they will in alternate position is
  • A
    $\frac{1}{{34}}$
  • $\frac{1}{{35}}$
  • C
    $\frac{1}{{17}}$
  • D
    $\frac{1}{{68}}$

Answer

Correct option: B.
$\frac{1}{{35}}$
b
(b) Four boys can be arranged in $4\,!$ ways and three girls can be arranged in $3\,!$ ways.

$\therefore $ The favourable cases $ = 4\,!\, \times \,3\,!$

Hence the required probability $=\frac{{  4\,!\, \times 3\,!}}{{7\,!}} = \frac{6}{{7 \times 6 \times 5}} = \frac{1}{{35}}$.

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