Question
From the figure , given below , calculate the lenth of CD .
✓
Answer
InΔ AED
$\frac{ AE }{ DE }=\tan 22^{\circ}$
⇒ AE = DE tan 22°= 15 x 0.404=6.06 m
InΔ ABC,
$\frac{ AB }{ BC }=\tan 47^{\circ}$
⇒ AB = BC tan 47° = 15 x 1.072= 16.09 m
∴ CD = BE = AB- AE= 10.03 m
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