MCQ
From the following $0.1\, M$ solution of compound, will be basic in nature
- A$NH_4Cl$
- ✓$CH_3COONa$
- C$Na_2SO_4$
- D$CH_3COONH_4$
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Given : $K_f (H_2O)$ = $2\ K\ kg\ mole^{-1}$, $K_{sp} (PbCl_2)$ = $4 × 10^{-6}$
(Assume molarity to be equal to molality) .....$^oC$