MCQ
From the following elements which of them has highest second ionisation potential
- A$N$
- ✓$O$
- C$C$
- D$F$
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$\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{SOCl}_{2} \longrightarrow \mathrm{A} \xrightarrow[AlCl_3]{Benzene} \mathrm{B} \xrightarrow[-OH]{KCN} \mathrm{C}$
$F{e^{ + 3}}\left( {aq} \right) + {e^ - } \to F{e^{2 + }}\left( {aq} \right);{E^o} = + 0.77\,V$
$A{l^{ + 3}}\left( {aq} \right) + 3{e^ - } \to Al\left( s \right);{E^o} = - 1.66\,V$
$B{r_2}\left( {aq} \right) + 2{e^ - } \to 2B{r^ - };{E^o} = + 1.09\,V$
Considering the electrode potentials, which of the following represents the correct order of reducing power?

| Substance | $H _{2}$ | $C ($ graphite $)$ | $C _{2} H _{6}( g )$ |
| $\frac{\Delta_{ C } H ^{\Theta}}{ kJmol ^{-1}}$ | $-286.0$ | $-394.0$ | $-1560.0$ |
The enthalpy of formation of ethane is ........ .
